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Java中使用FastJSON进行对象的序列化和反序列化
1.添加依赖,maven的pom.xml文件中添加以下依赖
com.alibaba fastjson 1.2.47
2.FastJSON序列化和反序列化工具类
import java.util.List;import com.alibaba.fastjson.JSONArray;import com.alibaba.fastjson.JSONObject;// JSON/对象转换类public class JsonUtils { /** * JSON字符串转换成对象 */ public staticT jsonStringToObject(String jsonStr,Class obj){ try{ return JSONObject.parseObject(jsonStr, obj); }catch(Exception e){ System.out.println("将JSON串{}转换成 指定对象失败:"+jsonStr); e.printStackTrace(); } return null; } /** * 对象转JSON */ public static String objectToJson(T obj){ try{ String json=JSONObject.toJSONString(obj); return json; }catch(Exception e){ System.out.println("将指定对象转成JSON串{}失败:"+obj.toString()); e.printStackTrace(); } return ""; } /** * List 对象转成json */ public static String listToJsonString(List objList){ try{ String json=JSONObject.toJSONString(objList); return json; }catch(Exception e){ System.out.println("将对象列表转成JSON串{}失败:"+objList.toString()); e.printStackTrace(); } return ""; } /** * json转换成对象列表List */ public static List jsonStringToList(String json,Class obj){ try{ return JSONArray.parseArray(json, obj); }catch(Exception e){ System.out.println("将JSON串{}转成对象列表失败:"+json); e.printStackTrace(); } return null; } /* * 将JSON串转换为JSONOBJECT */ public static JSONObject stringTOJSONObject(String json){ JSONObject jsonObject = null; try { jsonObject = JSONObject.parseObject(json); } catch (Exception e) { System.out.println("JSON串{} 转换成 JsonObject失败"+json); } return jsonObject; }}
3.使用
(1)序列化
Listusers=new ArrayList (); for(int i=0;i<20;i++){ User user=new User(); user.setName("FastJSON"+i); user.setAge(20+i); SimpleDateFormat dateformat = new SimpleDateFormat("yyyy-MM-dd"); user.setBirthday(dateformat.parse("1991-10-01")); user.setEmail("12345678"+i+"@qq.com"); // 序列化单个对象 String json=JsonUtils.objectToJson(user); users.add(user); // 序列化对象列表 // String json=JsonUtils.listToJsonString(users);}
(2)反序列化
// 反序列化单个对象 User u=JsonUtils.jsonStringToObject(json, User.class); System.out.println(u.toString()); // 将JSON串转换为JSONOBJECT JSONObject js=JsonUtils.stringTOJSONObject(json); System.out.println(js); // 反序列化对象列表 Listlist=JsonUtils.jsonStringToList(json, User.class); System.out.println(list);
4.FastJson的常见操作
(1)日期进行格式化 String dateToJson=JSON.toJSONString(new Date(), SerializerFeature.WriteDateUseDateFormat); System.out.println("使用JSON中的SerializerFeature特性格式化日期:"+dateToJson); String dateToJson2=JSON.toJSONStringWithDateFormat(new Date(), "yyyy/MM/dd"); System.out.println("JSON中自定义日期的输出格式:"+dateToJson2); (2)将Map转换成JSONObject然后添加元素,最后输出。 Mapmap = new HashMap (); map.put("name", "Gelpe"); map.put("age", 30); map.put("brithday",dateToJson); map.put("date",dateToJson2); // 将Map对象转成JSON字符串 String mapToJson=JSON.toJSONString(map); System.out.println("将MAP转成JSON: :"+mapToJson); // 将Map转换成JSONObject对象 JSONObject jsonObject = new JSONObject(map); System.out.println("JSONObject 1:"+jsonObject); (3)List转成JSON List list=new ArrayList (); list.add("shopping"); list.add("travel"); String listToJson=JSON.toJSONString(list); System.out.println("将List中存储的字符串转成JSON: :"+listToJson); (4) 向JSONObject中添加值 jsonObject.put("hobbies",list); (5) 从JSONObject中取值 System.out.println(jsonObject.get("hobbies")); System.out.println("JSONObject 2:"+jsonObject); (6)将List对象转成JSONArray,然后输出 List
以上操作,输出的内容:
使用JSON中的SerializerFeature特性格式化日期:"2018-12-01 10:58:46"JSON中自定义日期的输出格式:"2018/12/01"将MAP转成JSON: :{"date":"\"2018/12/01\"","brithday":"\"2018-12-01 10:58:46\"","name":"Gelpe","age":30}JSONObject 1:{"date":"\"2018/12/01\"","brithday":"\"2018-12-01 10:58:46\"","name":"Gelpe","age":30}将List中存储的字符串转成JSON: :["shopping","travel"][shopping, travel]JSONObject 2:{"date":"\"2018/12/01\"","hobbies":["shopping","travel"],"brithday":"\"2018-12-01 10:58:46\"","name":"Gelpe","age":30}将List中存储的MAP对象转成JSON:[{"address":"Beijing","city":"Beijing"},{"town":"wulukou","street":"Four street"}]将List中存储的MAP对象转成JSON并且格式化输出:[ { "address":"Beijing", "city":"Beijing" }, { "town":"wulukou", "street":"Four street" }]JSONArray:[{"address":"Beijing","city":"Beijing"},{"town":"wulukou","street":"Four street"}]JSONArray Content:{"address":"Beijing","city":"Beijing"}JSONArray Content:{"town":"wulukou","street":"Four street"}JSONObject 3:{"date":"\"2018/12/01\"","addressInfo":[{"address":"Beijing","city":"Beijing"},{"town":"wulukou","street":"Four street"}],"hobbies":["shopping","travel"],"brithday":"\"2018-12-01 10:58:46\"","name":"Gelpe","age":30}自定义对象转成JSON:{"age":24,"birthday":1543648393681,"name":"NB Person"}
JSON的解析:
(1)集合反序列化 Mapmap=JSON.parseObject(jsonString, Map.class); System.out.println("map get name:"+map.get("name")); System.out.println("map:"+map);(2)泛型的反序列化,使用TypeReference传入类型信息 Map map2=JSON.parseObject((jsonString,new TypeReference >(){}); System.out.println("map2 get name:"+map2.get("name")); System.out.println("map2 get hobbies:"+map2.get("hobbies")); System.out.println("map2:"+map2);
转载于:https://blog.51cto.com/59465168/2324480